Finally passed it. Phew. If I fail for the second time then I think I can become the joker of year. @___________@
To my amazement, questions that I answered this time were totally different from that of last time. So the difficulty of taking the test this time is about the same as last time. My wild guess is that the total number of questions in question bank, N is of four figures.
So let's estimate. I nearly forgot this is a Binomial case. There are total 50 questions need to be answered, so
the probability of getting the same question from previous test, p is 50/N
the probability of not getting, ... , q = 1-p
test going to be repeated for 50 times
assume the probability of getting none of the question same = 0.5 (half chance)
P(X=0) = 0.5, q = 0.9862, p = 0.013767,
so N = 3632
From the basic theory book, there are about 130 signs and rules, so if I assume the average number of possible of combination for each = 5 (by splitting, grouping, logic negation, multiple options and scenario comparison), it will give me 650 questions. Adding with 350 different simulated traffic cases by assumption, the practical total number of questions is 1000.
If N = 1000, then there is only 7.7% chance I will get none of the question same. So can I consider myself lucky? Haha.
Just to exercise my mind on the way back as I bought along my calculator. I can feel that my maths skills is rusting. @.@
Oh My God, you try to calculate the N using Binomial! Hahah.. I nearly forget this math! It's "nearly", so I still remember! Hahah.. no worries! XD XD XD
ReplyDeleteCongratulations for your pass! Otherwise I will laugh until "dead". Thanks for "saving my life".. Kekeke...
Your math skill is rusting? Ummm... Mine is much worse than yours. Haha, should I take some account course or something related to math? Oh, missed math so much! [Stop from thinking of such stupid things... hehe..]